Question

Most adults would not erase all of their personal information online if they could. A software firm survey of 480 randomly selected adults showed that 35​% of them would erase all of their personal information online if they could.Find the value of the test statistic?

Answer 1

-7.90

Explanation:

Let's write the null hypothesis (H0) and alternative hypothesis (Ha) from the claim statement

P = population proportion of adults who would erase all of their personal information online if they could

H_{0}:P=0.5

H1 P< 0.5

Let's write the given information:

n = sample size = 480

sample proportion =
`\hat p = 0.35`

formula of z test statistic for one sample proportion test is as follows:

`Z=\frac{\hat p-P}{\sqrt{(P*(1-P))/(n)}}`

plug the above values in the above formula we get

`Z =\frac{0.35-0.5}{\sqrt{(0.35(1-0.5))/(480)}}=Z=-7.85584`

So that the test statistic value is -7.90 (Rounded up to two decimal places)