Question

A certain planet has an escape speed V. If another planet has twice the radius and twice the mass of the first planet, its escape speed will be

1. V.
2. V/ 2
3. √.2
4. √ V.
5. 2V.

Answer 1

option A

Step-by-step explanation:

Escape velocity of the planet

`v = \sqrt{(GM)/(R)}`

now, it is given that

Second Planet

R₂ = 2R and M₂ = 2M

now escape velocity of the second planet

now,

`v'= \sqrt{(G(2M))/((2R))}`

on solving

`v'= \sqrt{(GM)/(R)}`

`v'= v`

escape velocity of the second planet is equal to first.

The correct answer is option A