Problem 1
The domain is
which in interval notation is [0, 6]
This is the set of t values where h(t) is positive or zero. Any other t values will make h(t) to be negative. So we ignore those t values. A negative height makes no sense.
The domain in the context of the problem means that the projectile is in the air from the time markers of t = 0 and t = 6. In short, the object is in the air for 6 seconds. It takes 6 seconds for it to hit the ground.
Here's how we can determine those t values. We plug in h(t) = 0 and solve for t.
h(t) = -16t^2 + 96t
-16t^2 + 96t = 0
-16t(t - 6) = 0
-16t = 0 or t - 6 = 0
t = 0/(-16) or t = 6
t = 0 or t = 6
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Problem 2
Draw a horizontal line through -3 on the y axis.
This horizontal line touches the blue graph at the points (-2,-3) and (2,3)
This means the inputs x = -2 and x = 2 lead to the output of y = -3
Therefore f(-2) = -3 and f(2) = -3
Answer: The solutions are x = -2 and x = 2