Question

Need help with number 2 , 4 , & 6 .

Answer 1

2. k can be any real number.

4. No real number can satisfy the equation.

6. y = - 3

Explanation:

2. 8 - 3(k + 2) = 2 - 3k

`$ \implies 8 - 3k - 6 = 2 - 3k $`

`$ \implies 2 = 2 $`

Any value of 'k' will solve the equation. That is, this equation has infinitely many solutions.

4. -7(a - 3) = 11 - 7a

`$ \implies -7a + 21 = 11 - 7a $`

`$ \implies 10 = 0 $` which is absurd. So, this equation has no solution.

6. 4(4y - 3) - (y - 5) = -52

`$ \implies 16y - 12 - y + 5 = - 52 $`

`$ \implies 15y = - 52 + 7 = -45 $`

`$ \implies y = - 3 $`

This equation has a unique solution.