Question

find the distance between two 74.0kg physics students that experience a gravitational force of 1.2 times 10 ^-8 N

Answer 1

distance between students: 5.51 meters

Step-by-step explanation:

We use the Newton's Universal Law of gravitation to solve this problem. This law states that the value of the gravitational force (Fg) between to masses m1 and m2 separated by a distance "d" is given by:

`F_g=G\,(m_1\,*\,m_2)/(d^2)`

where G is the Universal Gravitational Constant (
`G=6.67\,10^(-11)\,(m^3)/(kg\,s^2)`)

In our particular case, m1 = m2 = 74 kg. And the value of the gravitational force (Fg) is given as:
`1.2\,\,10^(-8)\,N`.

Then we can replace these values in the equation and solve for the unknown distance between the students. Notice that since all the quantities are given in SI units, the answer will also come in SI units (meters):

`F_g=G\,(m_1\,*\,m_2)/(d^2)\\1.2\,\,10^(-8)=6.67\,10^(-11)\,(74\,*\,74)/(d^2) \\d^2=6.67\,10^(-11)\,(74\,*\,74)/(1.2\,\,10^(-8))\\d^2=30.437\, m^2\\d=√(30.437) \,m\\d= 5.51 \,m`