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A line has a slope of 3 and includes the points (-2,q) and (-3,2). What is the value of q

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For this case we have that by definition, the slope of a line is given by:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where:


(x_ {1}, y_ {1})and
(x_ {2}, y_ {2}) are two points through which the line passes

According to the statement we have:


m = 3\\(x_ {1}, y_ {1}): (- 2, q)\\(x_ {2}, y_ {2}): (- 3,2)

Substituting we have:


3 = \frac {2-q} {- 3 - (- 2)}\\3 = \frac {2-q} {- 3 + 2}\\3 = \frac {2-q} {- 1}\\-3 = 2-q\\-3-2 = -q\\-5 = -q\\q = 5

Answer:

The value of q is 5

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