Answer:
Option D). 171 feet is correct
Explanation:
Given that a toy rocket is launched from 42 feet above the ground.
The height is rocket is given by f(t)=

To find the height of the rocket above the ground after 3seconds :
Given that f(0)=42
Take t=3
f(t)=

f(3)=

f(3)=

f(3)=

f(3)=171 feet
Therefore, option D). 171 feet is correct