Question

Find the sum of all solutions to the equation $3x(x+4) = 66$

Answer 1

Explanation:

Answer 2

-4

Explanation:

The given equation is

`3x(x+4)=66`

On simplification we get

`3x^2+12x=66`

Divide both sides by 3.

`x^2+4x=22`

`x^2+4x-22=0`

If a quadratic equation is defined as
`ax^2+bx+c=0`, then the sum of solutions is -b/a.

In the above equation a=1, b=4 and c=-22.

Sum of solutions
`=-(b)/(a)=-(4)/(1)=-4`

Therefore, the sum of all solutions is -4.