Answer:
The resistance of the leser = 40.5 Ω
Step-by-step explanation:
Energy stored in a battery (E) = V²t/R................. Equation 1
Where V= potential difference of the batteries, t = time, and R = resistance of the batteries.
Making R the subject of equation 1 above,
R = V²t/E................... substituting this values into equation 2
Where V= 3.0V, E = 20 kJ = 20 × 1000 = 20000 J, t = 25 hours = 25× 3600 = 90000 s
Substituting this values into equation 2,
R = 3²(90000)/20000
R = 40. 5 ohms (Ω)
The resistance of the leser = 40.5 Ω