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What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

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Answer:

mass of sulfur = 96 g

Step-by-step explanation:

no of moles of sulfur dioxide in
1.204* 10^(24) molecules =
(1.204* 10^(24))/(avagadro number )= (1.204* 10^(24))/(6.023* 10^(23))

= 2 moles

therefore mass of sulfur dioxide = moles×atomic number

=2×(16+32)

=96

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