Answer:
Number of touchdowns = 2
Number of extra points = 2
Number of field goals = 0
Explanation:
Let the number of touchdowns be "x", number of extra points be "y" and number of field goals be "z".
It is given that number of touchdowns = number of extra points.
Thus, x=y
Total points scored are 14.
Points scored by touch down are = (6)(x)
Points scored by extra points are = (1)(y) = x
Points scored by field goals are = (3)(z)
Thus, the equation becomes
![6x+y+3z = 6x+x+3z=7x+3z = 14](https://img.qammunity.org/2020/formulas/mathematics/high-school/y7qyts4mekfw48qxcev7fgmv6vcv32669i.png)
In matrice form, they can be represented as;
![\left[\begin{array}{ccc}6&1&3\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] (14)](https://img.qammunity.org/2020/formulas/mathematics/high-school/sfwelz6yoc2f7g5kkmun972qb3gbb655vb.png)
![x= (14-3z)/(7)](https://img.qammunity.org/2020/formulas/mathematics/high-school/y8kz6qbtcbwh7j3df9flycuxznyeo15l59.png)
now, x and z cannot be negative or fraction, only positive integers. Thus inserting values of z from 0 to 4,
The correct solution is x=y=2 and z=0.