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5x + 3y = -2

3x + 2y = -1
Solve the system of equations.
A) (-1, 1)
B) (1, -1)
C) (-1, -2)
D) (1/3, 1)

1 Answer

6 votes

Answer:

x = -1 , y = 1

Explanation:

Solve the following system:

{5 x + 3 y = -2 | (equation 1)

3 x + 2 y = -1 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = -2 | (equation 1)

0 x+y/5 = 1/5 | (equation 2)

Multiply equation 2 by 5:

{5 x + 3 y = -2 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

Answer: {x = -1 , y = 1

User James Pearce
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