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Debi has $1.65 in a collection of dimes and nickels the number of nickels is six more than the number of dimes find the number of each type of coin

User Jonhopkins
by
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1 Answer

3 votes

Answer:

There are 9 dimes and 15 nickels.

Explanation:

Let number of dimes be 'd' and number of nickels be 'n'.

Given:

Total amount Debi has = $1.65

Number of nickels is 6 more than dimes.

We know that,

1 dime = $0.10

∴ 'd' dimes = $
0.10d

1 nickel = $0.05

∴ 'n' nickels = $
0.05n

As per question,

Number of nickels = 6 + number of dimes


n=6+d--------1

Also, total amount = $1.65


0.10d+0.05n=1.65------2

Now, solving equations (1) and (2) for 'n' and 'd'.

Plug in the value of 'n' from equation (1) in equation (2). This gives,


0.10d+0.05(6+d)=1.65\\0.10d+0.30+0.05d=1.65\\0.10d+0.05d=1.65-0.30\\0.15d=1.35\\d=(1.35)/(0.15)=9

Therefore, the number of dimes are 9.

Number of nickels are = 9 + 6 = 15

User Paul Jowett
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