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Number 51 is 0.00150 ml to l

And number 53 is sodium hydrogen carbonate
need help on all of them

Number 51 is 0.00150 ml to l And number 53 is sodium hydrogen carbonate need help-example-1
User Scottclowe
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1 Answer

4 votes

Answer:

The answer to your question is

51.- 1.59 x 10⁻⁶

53.- NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl

Step-by-step explanation:

51.- Convert 0.00159 ml to liters

Use a rule of three

1000 ml -------------- 1 l

0.00159 ml --------- x

x = (0.00159 x 1) / 1000

x = 0.00000159 l = 1.59 x 10⁻⁶ l

53.- Sodium hydrogen carbonate (NaHCO₃) reacts with hydrochloric acid to produce salt, water and carbon dioxide.

Sodium hydrogen carbonate = NaHCO₃

Hydrochloric acid = HCl

Reaction

NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl

water = H₂O

carbon dioxide = CO₂

salt = NaCl

User Theintellects
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