Answer:
(a) ¹⁴₆ C ⇒ ¹⁴₇ N + ⁰₋₁ e
(b) ¹⁴⁰₅₅ Cs ⇒ ¹⁴⁰₅₆ Ba + ⁰₋₁ e
(c) ²³⁴₉₀ Th ⇒ ²³⁴₉₁ Pa + ⁰₋₁ e
Step-by-step explanation:
In a beta decay the nuclide emits a beta particle which are high enery electrons. The number of neutrons decreases by one and the atomic number increases also by one moving the nuclide one place to the right in the periodic table. The mass of the nuclide does not change since the mass of electron is negligible compared to the proton and neutron.
(a) ¹⁴₆ C ⇒ ¹⁴₇ N + ⁰₋₁ e
(b) ¹⁴⁰₅₅ Cs ⇒ ¹⁴⁰₅₆ Ba + ⁰₋₁ e
(c) ²³⁴₉₀ Th ⇒ ²³⁴₉₁ Pa + ⁰₋₁ e