Question

Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system?

Answer 1

The equilibrium consntant expression is:

Keq= (02) x (H2)^2/(H20)^2

Step-by-step explanation:

The equilibrium constant is calculated as the ratio between products and reagents raised to their stoichiometric coefficients. In this case, Water (H20) is a reagent and the respective products are Hydrogen (H2) and Oxygen (02)