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A sphere has a radius of 4 inches. What is the surface area of the smallest cube that could circumscribe the sphere?

1 Answer

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Answer:


SA=384\ in^2

Explanation:

we know that

The smallest cube that could circumscribe the sphere has a length side equal to the diameter of the sphere

In this problem

The radius of the sphere is
r=4\ in

The diameter of the sphere is two times the radius


D=2r=2(4)=8\ in

so

The length side of the cube is


b=8\ in

Remember that

The surface area of a cube is equal to the area of its six faces

so


SA=6b^2

substitute the value of b


SA=6(8)^2


SA=384\ in^2

User Radek Anuszewski
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