Answer:
joule
Step-by-step explanation:
Let m = mass of the car and v1 = initial velocity and v2 = final velocity
Given.
Initial velocity = 100 km/h
final velocity = 50 km/h
What is work done in the car to slow it from 100km/h to 50km/h?


The work done in the car to slow it from v1 to v2.
w=Δk






joule.
Therefore, the work done is
joule