Question

The 8.8 N weight is in equilibrium under the influence of the three forces acting on it. The F force acts from above on the left at an angle of α with the horizontal. The 6.7 N force acts from above on the right at an angle of 56◦ with the horizontal. The force 8.8 N acts straight down. F 6.7 N 8.8 N 56 ◦ α What is the magnitude of the force F? Answer in units of N.

Answer 1

F = 14.83N

Step-by-step explanation:

According to the given data:

F1 = [0, -8.8]N

F = [Fx,Fy]

F3 = [-6.7*cos(56°),-6.7*sin(56°)]N

The sum of forces on the x-axis, will be:

`Fx +F3_x=0` => Fx = 6.7*cos(56°)

Fx = 3.75N

The sum of forces on the y-axis, will be:

`Fy +F3_y + F1_y=0` => Fy = 6.7*sin(56°)+8.8

Fy = 14.35N

The magnitude of F is: F = 14.83N at an angle of 14.65° above the horizontal