Answer:
The equation of ellipse is

Explanation:
Given: An ellipse has
x-intercepts are (-3,0) and (3,0)
y-intercepts are (0,-1) and (0,1)
Let,
Length of major axis of ellipse is 2a and minor axis as 2b
Now,
The distance between two points is given by :
L=

The distance between x-intercepts (-3,0) and (3,0) :
X=

X=

X=6
The distance between Y-intercepts (0,-1) and (0,1) :
Y=

Y=

Y=2
Since, X>Y
An ellipse is parallel to x-axis
2a=6 and 2b=2
a=3 and b=1
From the equation of ellipse ;


