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if W(-10,4), X(-3,-1), and Y(-5,11) classify ∆WYX by it's sides. show all work to justify your answer.​

User Klaaz
by
8.5k points

1 Answer

4 votes

Answer:

The given triangle ∆WYX is isosceles triangle.

Explanation:

Given points are W(-10,4), X(-3,-1), and Y(-5,11) form triangle.

Distance between two points are given as

L=
\sqrt{(X2-X1)^(2) + (Y2-Y1)^(2) }

Now, Distance between W(-10,4) and X(-3,-1) is

WX=
\sqrt{(X2-X1)^(2) + (Y2-Y1)^(2) }

=
\sqrt{((-3)-(-10))^(2) + ((-1)-(4))^(2) }

=
\sqrt{(7)^(2) + (-5)^(2) }

=8.48

Now, Distance between W(-10,4) andY(-5,11) is

WY=
\sqrt{(X2-X1)^(2) + (Y2-Y1)^(2) }

=
\sqrt{((-5)-(-10))^(2) + (11-4)^(2) }

=
\sqrt{(5)^(2) + (7)^(2) }

=8.48

Now, Distance between X(-3,-1) andY(-5,11) is

XY=
\sqrt{(X2-X1)^(2) + (Y2-Y1)^(2) }

=
\sqrt{((-5)-(-3))^(2) + (11-(-1))^(2) }

=
\sqrt{(-2)^(2) + (12)^(2) }

=12.165

Since, WY=WX

The given triangle ∆WYX is isosceles triangle.

User Shisui
by
9.3k points

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