Question

The line y=-1/3x+4 passes through which of the following points

Answer 1

The points are (12, 0) & (0, 4).

Explanation:

The given equation of line is-

y = -
`(1)/(3)` x + 4...............................(i)

After taking L.C.M. both sides (i.e. Multiplying by 3 both sides)-

3 y = -x + 12.................................(ii)

Let x = 0 in equation (ii)-

3 y = 12

y = 4

Hence first point is ( 0, 4).

Now, let y = 0 in equation (ii)-

0 = - x + 12

-12 = - x

x = 12

therefore the points are ( 12, 0).

Hence the required points which passes through the line y = -1/3 x +4 are (0, 4) & ( 12, 0).

Answer 2

The line passes through the points ( 0 , 4 ) and ( 12 , 0 )

Explanation:

Given equation of line as :

y = -
`(1)/(3)` x + 4

Let the points through which the line passes are

(
`x_1` ,
`y_1` ) , (
`x_2` ,
`y_2` )

Now, for x = 0 , The line equation is y = -
`(1)/(3)` × 0 + 4

I.e for x = 0 , y = 0 + 4 = 4

So, (
`x_1` ,
`y_1` ) = ( 0 , 4 )

Again , for y = 0 , The line equation is 0 = -
`(1)/(3)` × x + 4

I.e for y = 0 , The line equation is 4 =
`(x)/(3)`

Or, for y = 0 , x = 4 × 3 = 12

So , (
`x_2` ,
`y_2` ) = ( 12 , 0 )

Hence The line passes through the points ( 0 , 4 ) and ( 12 , 0 ) Answer