Question

SOME ONE PLEASE ANSWER ASAP NEED EXPLAIN FULL STEPS​

Answer 1

`{ \tt{( ( - 4)/(9) * (63)/(28)) - ( (33)/(66) * ( - 51)/(17) ) + ( (5)/(8) * (4)/(10)) }} \\ \\ = { \tt{( ( - 4)/(28) * (63)/(9)) - ( (1)/(2) * ( - 3)/(1) ) + ( (5)/(10) * (4)/(8) )}} \\ \\ { \tt{ = ( - 1) - ( - (3)/(2) ) + ( (1)/(4)) }} \\ \\ = { \tt{ (3)/(4) }}`

Answer 2

`\sf (3)/(4)`

Explanation:

Given expression:

`\implies \sf \left((-4)/(9) * (63)/(28)\right)-\left((33)/(66) * (-51)/(17)\right)+\left((5)/(8) * (4)/(10)\right)`

`\textsf{Apply the fraction rule} \quad (a)/(b) * (c)/(d)=(a * b)/(c * d):`

`\implies \sf \left((-4*63)/(9*28) \right)-\left((33 * -51)/(66 * 17)\right)+\left((5*4)/(8*10) \right)`

Multiply the numbers:

`\implies \sf \left((-252)/(252) \right)-\left((-1683)/(1122)\right)+\left((20)/(80) \right)`

Reduce the fractions:

`\implies \sf -1-\left((-3)/(2)\right)+\left((1)/(4) \right)`

`\textsf{Apply rule}\quad \:a-\left(-b\right)=a+b:`

`\implies \sf -1+(3)/(2)+(1)/(4)`

Adjust the fractions based on the LCM of 4:

`\implies \sf (-4)/(4)+(6)/(4)+(1)/(4)`

`\textsf{Apply the fraction rule} \quad (a)/(c)+(b)/(c)=(a+b)/(c):`

`\implies \sf(-4+6+1)/(4)`

Add the numbers in the numerator:

`\implies \sf (3)/(4)`