Question

A string is tied at both ends, and a standing wave is established. The length of the string is 2 m, and it vibrates in the fundamental mode ( n = 1).1) If the speed of waves on the string is 60 m/s, calculate the wavelength of the waves. (Express your answer as an integer.)2) If the speed of waves on the string is 60 m/s, calculate the frequency of the waves. (Express your answer to two significant figures.)

Answer 1

Wavelength = 1.33 m

Frequency = 721.80 Hz

Step-by-step explanation:

Given that

Length ,L= 2 m

V= 60 m/s

The wavelength λ given as

`\lambda =(2 L)/(3)`

`\lambda =(2* 2)/(3)`

λ = 1.333 m

We know that the velocity given as

V = f λ

60= f x 1.33

f = 721.80 Hz