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If I have 27L of a 0.003 M solution of salt water, how many molecules of salt do I have?​

1 Answer

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Answer:

no. of molecules of salt = 5.046 x 10²²

Step-by-step explanation:

Data given:

Volume of the Solution = 27 L

Molarity of the Solution = 0.003

Number of molecules of salt = ?

Solution:

First find number of moles of salt

Formula used

Molarity = moles of solute / L of solution

Rearrange the above equation

moles of solute = Molarity x L of Solution

Put values in above equation

moles of solute = 0.003 x 27 L

moles of solute = 0.081 moles

Now we can find the number of molecules of salt

Formula used to find no. of molecules

no. of moles = no. of molecules / Avogadro's number

Avogadro's number = 6.23 x 10²³

Now rearrange the above equation

no. of molecules = no. of moles x Avogadro's number . . . . . . . (1)

Put values in Equation 1

no. of molecules = 0.081 moles x 6.23 x 10²³

no. of molecules = 5.046 x 10²²

So,

no. of molecules of salt = 5.046 x 10²²

User Tamim Al Manaseer
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