Question

A person tosses a ball from the ground up into the air at an initial speed of 10 m/sec and an initial angle of 43° off the ground. What is the component of the velocity of the ball in the horizontal direction just before the ball hits the ground? Assume that both velocity components were positive when the ball was first thrown.

Answer 1

Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s

Step-by-step explanation:

In horizontal direction there is acceleration or deceleration for a ball tossed upward at an initial angle of 43° off the ground.

So the horizontal component of velocity always remains the same.

Horizontal component of velocity is the cosine component of velocity.

Initial velocity, u = 10 m/s

Angle, θ = 43°

Horizontal component of velocity = u cosθ

Horizontal component of velocity = 10 cos43

Horizontal component of velocity = 7.31 m/s

Since the horizontal velocity is unaffected, we have

Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s