Answer:
Frequency of dominant allele (p) = 0.471
Frequency of the recessive allele (q) = 0.529
Frequency of homozygous recessive genotype (q^2)= 0.28
Frequency of homozygous dominant genotype (p^2) = 0.222
Frequency of heterozygous dominant genotype (2pq) = 0.498
Step-by-step explanation:
Out of 500 individuals, proportion of the homozygous recessive genotype (the people that can not taste PTC) = 140
Frequency of homozygous recessive genotype (q^2)= 140/500 = 0.28
Frequency of the recessive allele (q) = square root of 0.28 = 0.529
Since p+q = 1 (p = frequency of dominant allele and q = frequency of recessive allele)
Frequency of dominant allele (p) = 1-q = 1-0.529 = 0.471
Frequency of homozygous dominant genotype (p^2) = 0.471 x 0.471 = 0.222
Frequency of heterozygous dominant genotype (2pq) = 2 x 0. 471 x 0.529 = 0.498