Question

What is the equation of the line which includes points (-3, 2) and (1, 6)?

O
y = x - 5
O y = x + 5
Ov=+6
Ov=-4x+6

Answer 1

required equation of line is y=x+5

Explanation:

equation of line passing through points
`(x_1,y_1)` and
`{ x_2,y_2)`

`y-y_1`=
`(y_2-y_1)/(x_2-x_1)`\times{x-x_1}

put the co-ordinate (-3,2) and(1,6)

y-2=
`(6-2)/(1+3)`\times{x+3}

y-2=x+3

y=x+5 answer