Answer:
The total length of the three hallways is 241.59 meter.
Explanation:
Since we need to count the hallways in clockwise direction, We need to find the distance between A(-20, 60) and D(50, 75), D(50, 75) and C(50, -25), C(50, -25) and B(-20, -25).
Then we need to add the three of them.
Hence all we need to do is to find the difference between the respective points.
The length of the hallway AD is =
≅ 71.59
Similarly, for DC is =
and CB is =
![\sqrt{[(50 + 20)^(2) + (- 25 + 25)^(2) ]} = \sqrt{70^(2) + 0} = <strong>70</strong>](https://img.qammunity.org/2020/formulas/mathematics/middle-school/seru47y84i2w84ejgdlnlxm8qv1zh3efc5.png)
Hence, the total length of the hallways is
