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Please help cant find anywhere

Please help cant find anywhere-example-1

1 Answer

3 votes

Answer:

The option is first one that is


(m^(7)n^(3)n)/(m)

Explanation:

Given:


(m^(7)n^(3))/(mn^(-1) ),m\\eq 0,n\\eq 0

After negative exponent eliminated we get


(m^(7)n^(3)n)/(m)

Negative exponent :

The variable containing negative powers. Here the variable( n⁻¹) is negative exponent.

Law of indices


a^(-1) = (1)/(a)\\\\Here\\n^(-1) = (1)/(n)\\\\


\\\textrm{Using law of indices we get}\\(m^(7)n^(3))/(mn^(-1) )=(m^(7)n^(3))/(m(1)/(n) ) }\\\\ (m^(7)n^(3))/(mn^(-1) )=(m^(7)n^(3)n)/(m)

User Dan Udey
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