Question

Please help cant find anywhere

Answer 1

The option is first one that is

`(m^(7)n^(3)n)/(m)`

Explanation:

Given:

`(m^(7)n^(3))/(mn^(-1) ),m\\eq 0,n\\eq 0`

After negative exponent eliminated we get

`(m^(7)n^(3)n)/(m)`

Negative exponent :

The variable containing negative powers. Here the variable( n⁻¹) is negative exponent.

Law of indices

`a^(-1) = (1)/(a)\\\\Here\\n^(-1) = (1)/(n)\\\\`

`\\\textrm{Using law of indices we get}\\(m^(7)n^(3))/(mn^(-1) )=(m^(7)n^(3))/(m(1)/(n) ) }\\\\ (m^(7)n^(3))/(mn^(-1) )=(m^(7)n^(3)n)/(m)`