Question

What is the equation of a line through points (-3,7) and (2,5)

Answer 1

y-7=-2/5(x+3)

Explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(5-7)/(2-(-3))

m=-2/(2+3)

m=-2/5

y-7=-2/5(x-(-3))

y-7=-2/5(x+3)