Question

Find the real/and or imaginary solutions by factoring:

1) x^2-12x=-27

2. x^3-6x^2+6x=0

Answer 1

1) x = 9, 3

2)
`x = 0, 3+√(3) , 3+√(3)`

Explanation:

1)
`x^2-12x=-27\\x^2-12x+27 = 0\\`

After factoring:

`(x-9)(x-3) = 0\\x = 9, 3`

2)
`x^3-6x^2+6x=0\\x(x^2-6x+6)=0\\x(x-3-√(3))(x-3+√(3))`

`x = 0, 3+√(3) , 3+√(3)`