How many atoms of Al(OH)3 in a 72 gram sample? please show work

asked Feb 2, 2020 169k views

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Answer:

5.559*10^(23) atoms

Step-by-step explanation:

Molar Mass of Al(OH)3 = 78 g/mol

(72g/78g/mol)*(6.022*10^(23)atoms/mol) = 5.559*10^(23) atoms in 72 grams of Al(OH)3

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