Question

What would be the midpoint of the (2a, 4b) and (-4a, 0)

(2a, -b)


(-a, 2b)


(-a, b)


(2a, 2b

Answer 1

The midpoint M is defined as
`M\Big((x_1+x_2)/(2),(y_1+y_2)/(2)\Big)`

where
`P_1(x_1,y_1),P_2(x_2,y_2)`.

So we have

`M\Big((2a-4a)/(2),(4b+0)/(2)\Big)=\boxed{M\Big(-a,2b\Big)}`

Hope this helps.