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3 votes
Question

In the last 6 years, the population of San Francisco has grown at a rate of 1.26% per year to 870,887. If this rate continues,
what will be the population in 5 more years? Round your answer to the nearest whole number.

User Brankica
by
5.7k points

2 Answers

4 votes

Answer:

927,518

Explanation:

User BiscuitBaker
by
6.1k points
1 vote

Answer:


927,154\ people

Explanation:

we have a exponential function of the form


y=a(b^x)

where

y is the population of San Francisco

x is the number of years

a is the initial population

b is the base

r is the rate of grown

b=(1+r)

In this problem we have


r=1.26\%=1.26/100=0.0126


b=1+0.0126=1.0126

ordered pair (6, 870,887)

substitute in the exponential function
y=a(b^x)


870,887=a(1.0126^6)

Solve for a


a=870,887/(1.0126^6)


a=807,857\ people

so

The exponential function is equal to


y=807,857(1.0126^x)

In 5 more years the number of years will be equal to

6+5=11 years

For x=11 years

substitute the value of x in the exponential function and solve for y


y=807,857(1.0126^(11))


y=927,154\ people

User Yoshinbo
by
6.1k points