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Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative.)f(x) = 9ex + 4 sec2x

1 Answer

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Answer:


\int\ {f(x)} \, dx = 9e^x + 2ln(sec(2x) + tan(2x)) + C

Explanation:

think of the function having two parts,
9e^x and
4sec(2x)

and integrate them separately.

  • First integrate
    9e^x


\int\ {9e^x} \, dx \\

since 9 is a constant you


9\int\ {e^x} \, dx\\


9e^x

  • Next integrate
    4sec(2x)


\int\ {4sec(2x)} \, dx \\4\int\ {sec(2x)} \, dx \\

we can use u-substitution
u = 2x and
du =2dx


4\int\ {sec(u)} \, (du)/(2) \\2\int\ {sec(u)} \, du\\

think of it as only integrating sec(x)


2(ln(sec(u) + tan(u)))\\2(ln(sec(2x) + tan(2x)))\\

  • Now combine the two answers and include the constant of integration (+C)

Answer::
9e^x + 2ln(sec(2x) + tan(2x)) + C\\

User Quinn
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