Answer:
A ) Hence The interest for the car loan is $ 4,310
B ) Hence The interest for the car loan is $ 3,152
Explanation:
Given as :
The loan for the car = $ 20,000
The rate of interest of car loan = 5 % compounded annually
A ) The period of loan = 48 months = 4 years
Let the interest of the loan = CI
From compounded method
Amount = Principal ×
![(1 + (\textrm Rate)/(100))^(\textrm time)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xqiqzu2h0e94nx7z5v5mep64toif4rz1l1.png)
Or, Amount = $ 20,000 ×
![(1 + (\textrm 5)/(100))^(\textrm 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p6vtpzzcxlne9d3c58ga6j0piojc47a36f.png)
Or, Amount = $ 20,000 ×
![(1.05)^(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d299o31kaf0e7c8e8tk52omivsp016xc53.png)
Or, Amount = $ 20,000 × 1.2155
∴ Amount = $ 24310
So, Interest = Amount - Principal
Or, CI = $ 24,310 - $ 20,000
∴ CI = $ 4,310
Hence The interest for the car loan is $ 4,310
B ) The loan for the car = $ 20,000
The rate of interest of car loan = 5 % compounded annually
The period of loan = 3 years
Let the interest of the loan = CI
So,
From compounded method
Amount = Principal ×
![(1 + (\textrm Rate)/(100))^(\textrm time)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xqiqzu2h0e94nx7z5v5mep64toif4rz1l1.png)
Or, Amount = $ 20,000 ×
![(1 + (\textrm 5)/(100))^(\textrm 3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wqkdurkgpa03ml8elsytvxw407vrie6zn8.png)
Or, Amount = $ 20,000 ×
![(1.05)^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f3te7zda04tjq7h0fabgd8gfchwf77nkky.png)
Or, Amount = $ 20,000 × 1.1576
∴ Amount = $ 23,152
So, Interest = Amount - Principal
Or, CI = $ 23,152 - $ 20,000
∴ CI = $ 3,152
Hence The interest for the car loan is $ 3,152