Question

In the first step of glycolysis, the given two reactions are coupled. reaction 1: glucose + P i ⟶ glucose - 6 - phosphate + H 2 O Δ G = + 13.8 k J / mol reaction 2: ATP + H 2 O ⟶ ADP + P i Δ G = − 30.5 k J / mol Answer the four questions about the first step of glycolysis. Is reaction 1 spontaneous or nonspontaneous?

Answer 1

non-spontaneous

Step-by-step explanation:

The reaction which shows the removal of the terminal phosphate from the ATP is shown below:

`Glucose+P_i\rightarrow Glucose-6-phosphate+H_2O`

The Gibbs' free energy change of this reaction,
`\Delta G^0=+13.8\ kcal/mol`

For a reaction of be spontaneous,
`\Delta G^0<0`

The Gibbs' free energy change is positive which means that the reaction is energetically unfavorable. or non-spontaneous.