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A thin wire has the shape of the quarter circle in the first quadrant. The circle is centered at the origin with radius a. Let rho = kxy be the linear density of the wire. Here k > 0 is just a constant.
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A thin wire has the shape of the quarter circle in the first quadrant. The circle is centered at the origin with radius a. Let rho = kxy be the linear density of the wire. Here k > 0 is just a constant. Find the mass and the center of mass of the wire

User Justin Khoo
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5.4k points

1 Answer

3 votes

Answer:

mass =
(k*a^(3) )/(2)

COM of arc (
(2a)/(3),
(2a)/(3))

Step-by-step explanation:

By using cylendrical coordinate system find total mass and COM position.

This arc is symmetric about x=y thus COM lies on this line.

Rest is in attachment.

A thin wire has the shape of the quarter circle in the first quadrant. The circle-example-1
User Rahul Juyal
by
5.6k points
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