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Calculate the standard emf of a cell that uses the Mg/Mg2+ and Cu/Cu2+ half-cell reaction at 25°C. E o = V Write the equation for the cell reaction that occurs under standard-state conditions. Be sure to include the physical state of each species in the reaction.

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Answer with Explanation:

We have to calculate the standard emf of a cell.

Consider
E^0_(Mg/Mg+2)=-2.37 v


E^0_(Cu/Cu+2)=0.34 V

T=
25^(\circ)=25+273=298 K

Anode half reaction:
Mg(s)\rightarrow Mg+2(aq)^+2e-

Cathode half reaction:
Cu+2(aq)+2e-\rightarrow Cu(s)

Overall reaction of cell :


Mg(s)+Cu+2(aq)\rightarrow Mg+2(aq)+Cu(s)

Cathode :The electrode which gains electrons.

Anode: The electrode which losses electrons.

We know that standard emf of the cell


E^0_(cell)=E_(cathod)-E_(Anode)


E^0_(cell)=0.34+2.37=2.71 V

Hence, the standard emf of a cell=2.71 V

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