30.6k views
4 votes
Quiz 3

A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.
If we choose a marble, then another marble without putting the first one back in the bag, what is the
probability that the first marble will be green and the second will be red?
Report a problem

User Junioregis
by
8.4k points

1 Answer

4 votes

Answer:

1/12

Explanation:

2 red marbles + 3 green marbles + 4 blue marbles = 9 marbles

First drawing:

You want a green marble out of 3 green marbles out of the total of 9 marbles.

p(green marble) = 3/9 = 1/3

Second drawing:

After drawing the green marble, there are 8 marbles left. There are 2 red marbles.

p(red marble) = 2/8 = 1/4

p(green then red) = 1/3 * 1/4 = 1/12

User Monnomcjo
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories