Question

Use the equation below to determine how many grams of CO are needed to react with an excess of Fe2O3 to produce 104.9 g Fe? You must show all of your work to receive credit.

Molar Mass Information:
Fe= 55.85 g/mol
C= 12.01 g/mol
O= 15.99 g/mol
(3 points)

Please I'm so confused!!!

Answer 1

1.40 * 10 ^3 g

Step-by-step explanation:

Answer 2

78.89g

Step-by-step explanation:

3CO+Fe2O3=2fe+3CO2 from the equation. 3moles of CO produced 2moles of Fe thus. Molar mass of CO=28 and Fe=55.85. Going by the formulae n= mass/molar mass. Mass of each will be n× molar mass. Thus. 28×3=84. 55.85×2=111.7. Thus,111.7g was produced by 84g of CO. Then 104.9g of Fe will be produced by 84/111.7×104.9=78.89g