Question

What is the vertex of the quadratic function below?

y=x² +12%-7
O A. (-6,-43)
OB. (-6,-29)
O C. (6,3)
OD. (6,29)

Answer 1

A

Explanation:

assuming you meant y = x² + 12x - 7 , then

given a quadratic in standard form

y = ax² + bx + c (a ≠ 0 )

the x- coordinate of the vertex is

x = -
`(b)/(2a)`

y = x² + 12x - 7 ← is in standard form

with a = 1 , b = 12 , then x- coordinate of vertex is

x = -
`(12)/(2)` = - 6

substitute x = - 6 into the equation for corresponding y- coordinate

y = (- 6)² + 12(- 6) - 7

= 36 - 72 - 7

= - 43

vertex = (- 6, - 43 )