Question

A horizontal cable pulls a 200-kg cart along a horizontal track. The tension in the cable is 500N. Starting from rest, how long will it take the cart to reach a speed of 8 m/s? How far will it have gone?

Answer 1

s = 12.8 m

Step-by-step explanation:

given,

mass of the cart = 200 Kg

tension of the cable = 500 N

initial velocity = 0 m/s

final velocity = 8 m/s

using formula

F = mass x acceleration

500 = 200 x a

`a =(500)/(200)`

`a =2.5\ m/s^2`

using equation of motion

v² = u² + 2 as

8² = 0² + 2 x 2.5 x s

64 = 5 s

s = 12.8 m

the distance travel used to reach speed of 8 m/s is equal to 12.8 m