Coordinate of image triangle is M'(-6,-2),N'(-1,7) and P'(3,4)
Explanation:
The given triangle MNP has coordinates of M(-2,6), N(7,1), and P(4,-3)
In matrix form, It can be written as :
![\left[\begin{array}{ccc}-2&7&4\\6&1&-3\\\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9qy5lmsqfe3ywn40o1m0258xk49l26zn5s.png)
Triangle has to rotate by angle of 90 degree at origin.
Counterclockwise Rotation matrix is given by :
![\left[\begin{array}{ccc}cos\theta&-sin\theta\\sin\theta&cos\theta\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/twqc7gz1j7agaccwtzd5ty0kfro35vr8qt.png)
For

![\left[\begin{array}{ccc}0&-1&\\1&0\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/57uwugoztbarke3zr9um9ch4x0ss89mmmg.png)
Image of triangle MNP will be
=
![\left[\begin{array}{ccc}-2&7&4\\6&1&-3\\\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9qy5lmsqfe3ywn40o1m0258xk49l26zn5s.png)
=
![\left[\begin{array}{ccc}-6&-1&3\\-2&7&4\\\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vi170bcyzz1lrotskgqkxmm6ulvwmml1f8.png)
Thus,
The coordinate of image triangle is M(-6,-2),N(-1,7) and P(3,4)