Question

HELPPPPPwhat is the value of x in the rhombus below super easy

Answer 1

28°

Explanation:

Recall that the diagonals of a rhombus intersect at 90°

If we let the center of rhombus (where the diagonals intersect) be O,

then ∠AOB = 90°

because all interior angles of a triangle sum to 180°,

∠AOB + ∠OAB + ∠ABO = 180°

90 + (x+6) + 2x = 180 (subtract 90 from both sides)

(x+6) + 2x = 90

3x + 6 = 90 (subtract 6 from both sides)

3x = 84

x = 84/3 = 28°