Question

What is the energy of a photon (in units of h) that has a wavelength of 300 nm?

(c = 3.00 x 108 m/s)


1 x 10^17 h
1 x 10^15 h
1 x 10^6 h
1 x 10^-2 h

Answer 1

`Energy=1* 10^(15)h\ J`

Step-by-step explanation:

Considering:-

`E=\frac {h* c}{\lambda}`

Where,

h is Planck's constant having value
`6.626* 10^(-34)\ Js`

c is the speed of light having value
`3* 10^8\ m/s`

`\lambda` is the wavelength of the light

Given, Wavelength = 300 nm

Also, 1 m =
`10^(-9)` nm

So,

Wavelength =
`300* 10^(-9)` m

Applying in the equation as:-

`E=\frac {h* c}{\lambda}`

`E=(h* 3* 10^8)/(300* 10^(-9))\ J`

`Energy=1* 10^(15)h\ J`