Question

The length of a rectangle is 7 yd more than double the width, and the area of the rectangle is 99 yd^2. find the dimensions of the rectangle.

Answer 1

w(2w+7) = 99

2w^2 + 7w - 99 = 0

( 2w - 11 )(w + 9 ) = 0

w+9=0 results in negative measures

2w-11 = 0

2w = 11

w = 11/2 = 5.5

L = 2w + 7 = 18