Question

The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).

4Al + 3O2 ----> 2Al2O3

The molar mass of O2 is 32.0 g/mol. What mass, in grams, of O2 must react to form 3.80 mol of Al2O3?

60.8
81.1
122
182

Answer 1

D. 182

Step-by-step explanation:

right on e2020

Answer 2

182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.

Step-by-step explanation:

`4Al + 3O_2\rightarrow 2Al_2O_3`

Moles of aluminum oxide = 3.80 mole

According to reaction, 2 moles of aluminum oxide is obtained from 3 moles of oxygen gas.

Then 3.80 moles of aluminum oxide will be obtained from:

`(3)/(2)* 3.80 mol=5.7 mol` of oxygen gas.

Mass of 3.80 moles of oxygen = 5.7 mol × 32 g/mol = 182.4 g ≈ 182 g

182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.