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Multiply the binomials (6a^3-5) (4a^3-11a)

User Bkilinc
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1 Answer

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For this case we must multiply the following expression:


(6a ^ 3-5) (4a ^ 3-11a) =

We apply distributive property considering that:


+ * + = +\\+ * - = -\\- * - = +

So:


6a ^ 3 * 4a ^ 3-6a ^ 3 * 11a-5 * 4a ^ 3 + 5 * 11a =

To multiply powers of the same base, we place the same base and add the exponents.


24a^ {3 + 3} -66a^ {3 + 1} -20a ^ 3 + 55a =\\24a ^ 6-66a ^ 4-20a ^ 3 + 55a

Answer:


24a ^ 6-66a ^ 4-20a ^ 3 + 55a

User Ethan Marcus
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